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Sixteen out of the 51 cards left in the pack are worth ten, so the branch to the F in the top right has a probability of 16/51 - one way of getting a.


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The % odds of being dealt a blackjack is an average probability, based on no prior information. Of course if you were to keep track of the total.


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We first present the probabilities attached to card dealing and initial predictions. In making this calculus, circumstantial information such as fraudulent dealing is.


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How To Deal Cards In Blackjack

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What are the odds of you getting dealt a 20 and the dealer drawing to 21 in blackjack? Ad by DuckDuckGo.


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Sixteen out of the 51 cards left in the pack are worth ten, so the branch to the F in the top right has a probability of 16/51 - one way of getting a.


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The farthest I've really come is that the odds of the first player getting dealt a blackjack is First case: Odds of getting an Ace are


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Sixteen out of the 51 cards left in the pack are worth ten, so the branch to the F in the top right has a probability of 16/51 - one way of getting a.


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When to Split Pairs in Blackjack - Gambling Tips

Hot Network Questions. Post as a guest Name. Sign up to join this community. Home Questions Tags Users Unanswered. Your calculation for the first player is correct. Then for the other player we either give them two aces from the 3 that are left, give them one ace from the 3 that are left and 1 of the 32 cards, or give them two non-aces from the 47 non-aces that are left. Asked 5 years, 3 months ago. Nolohice 5 5 silver badges 12 12 bronze badges. Viewed 19k times. The probability of both getting blackjack is just the probability of the player getting blackjack and the subsequent probability of the dealer also getting blackjack:. What posts should be escalated to staff using [status-review], and how do Iā€¦. I don't know if this will get you any closer to a closed form solution, but maybe it helps you think about it. Sign up using Email and Password. It only takes a minute to sign up. The use of neither indicates that. This is not quite correct, as the fact that the first player did not get blackjack enriches the average deck with cards that could make a blackjack for the second player. With a branching factor of five I know , we have two aces, once ace, two whatevers, one 10, two 10s. Question feed. Active Oldest Votes. Active 1 year, 7 months ago. The naive assumption is that the chance of each player getting blackjack is independent of the others. So I deleted the more complicated answer I tried to give earlier. I can't help but wonder if there perhaps is a less hideous way of acquiring the same answer though. Michael Cotton Michael Cotton 3 3 silver badges 6 6 bronze badges. Email Required, but never shown. Related 0. Featured on Meta. Because the chance of one player getting blackjack is small, the enrichment is small as well, so this is not far off. The outermost branches are short, but the inside of the tree is massive Hopefully this at least helps you contextualize the problem.

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Ross Millikan Ross Millikan k 24 24 gold badges silver badges bronze badges. This happens every time. Blackjack Probability Ask Question. We're switching to CommonMark. Sign up or log in Sign up using Google. Suppose that you are playing blackjack against the dealer.